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6a^2+9a-80=0
a = 6; b = 9; c = -80;
Δ = b2-4ac
Δ = 92-4·6·(-80)
Δ = 2001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{2001}}{2*6}=\frac{-9-\sqrt{2001}}{12} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{2001}}{2*6}=\frac{-9+\sqrt{2001}}{12} $
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